61. The refracting angle of a prism is ’ A ’, and refractive index of the material of the prism is cot(A/2). The angle of minimum deviation is :
(a) 180° − 2 A
(b) 90° − A
(c) 180° + 2 A
(d) 180° − 3 A
Answer : (a) 180° − 2 A
\(\frac{\sin i}{\sin r} = \mu = \cot \frac{A}{2}\)
\(\frac{\sin \frac{\delta_{min}+A}{2}}{\sin \frac{A}{2}} = \frac{\cos \frac{A}{2}}{\sin \frac{A}{2}}\)
\(\sin \frac{\delta_{min}+A}{2} = \sin \left(90^\circ - \frac{A}{2}\right)\)
\(\frac{\delta_{min}+A}{2} = 90^\circ - \frac{A}{2}\)
\(\delta_{min} = 180^\circ - 2A\)
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