51. A ball is thrown vertically downward with a velocity of 20 m/s from the top of a tower. It hits the ground after some time with a velocity of 80 m/s. The height of the tower is: (g = 10 \(m/s^2\))
(a) 340 m
(b) 320 m
(c) 300 m
(d) 360 m
Answer : (c) 300 m
\( v^2 = u^2 + 2as \)
\( 80^2 = 20^2 + 2(10)h \)
\( 6400 = 400 + 20h \)
\( h = \) \( \frac{6400 - 400}{20} \)\( = 300 \, \text{m} \)
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