74. In an astronomical telescope in normal adjustment a straight black line of length L is drawn on inside part of objective lens. The eyepiece forms a real image of this line. The length of this image is l. The magnification of the telescope is :
(a) \( \dfrac{L}{l} - 1 \)
(b) \( \dfrac{L + l}{L - 1} \)
(c) \( \dfrac{L}{l} \)
(d) \( \dfrac{L}{I} + 1 \)
Answer : (c) \( \dfrac{L}{I} \)
\( M = \dfrac{h'}{h} \)
\( M = \dfrac{v}{u} \)
\( \dfrac{1}{f} = \dfrac{1}{v} - \dfrac{1}{u} \)
\( M = \dfrac{f}{f+u} \)
\( = \dfrac{f_e}{f_e - [f_e + f_o ] } \)
\( \dfrac{-l}{+L} = \dfrac{f_e}{-f_o} \)
\( \dfrac{f_o}{f_e} = \dfrac{L}{l} \)
\( M_{\text{telescope}} = \dfrac{f_o}{f_e} = \dfrac{L}{l} \)
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