14. In the Young’s double-slit experiment, the intensity of light at a point on the screen where the path difference is λ is K, ( λ being the wave length of light used). The intensity at a point where the path difference is λ/4, will be :
(a) K
(b) K/4
(c) K/2
(d) 0
Answer : (c) K/2
\( I = I_1 + I_2 + 2\sqrt{I_1 I_2}\cos \phi \)
\( \text{phase diff.} = \dfrac{2\pi}{\lambda} \times \dfrac{\lambda}{4} \)
\( = \dfrac{\pi}{2} \)
\( I = I_1 + I_2 + (0) \)
\( = 2I_1 \)
\( = 2 \dfrac{K}{4} \)
\( = \dfrac{K}{2} \)
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