19. A particle moves along a straight line OX. At a time t (in seconds) the distance x (in metres) of the particle from O is given by \(x = 40 + 12t − t ^3\) . How long would the particle travel before coming to rest?
(a) 40 m
(b) 56 m
(c) 16 m
(d) 24 m
Answer : (b) 56 m
\( x = 40 + 12t - t^3 \)
\( v = \)\( \frac{dx}{dt} \)\( = 12 - 3t^2 = 0 \)
\( \rightarrow t = 2 \)
\( x_{(t=2)} = 40 + 12(2) - (2)^3 \)
\( = 56 m \)
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