31. The displacement ’ x ’ (in meter) of a particle of mass ’ m ’ (in kg ) moving in one dimension under the action of a force, is related to time ’ t ’ (in sec) by t = √x+ 3. The displacement of the particle when its velocity is zero, will be
(a) 2 m
(b) 4 m
(c) 0 m
(d) 6 m
Answer : (c) 0 m
\( t = \sqrt{x} + 3 \)
\( \rightarrow t - 3 = \sqrt{x} \)
\( \rightarrow x = (t - 3)^2 \)
\( v = \)\(\frac{dx}{dt}\)\( = 2(t - 3) \)
\( 2(t - 3) = 0 \)
\( \rightarrow t = 3 \, \text{s} \)
\( x_{t=3} = 0 \, \text{m} \)
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