A particle of mass m is moving with a uniform velocity v1. It is given an impulse such that its velocity becomes v2. The impulse is equal to
NEET 1990
(a) m[|v2| − |v1|]
(b) 1/2 m (v2 ^2 - v1^2)
(c) m[v1 + v2]
(d) m[v2 − v1]
A particle of mass m is moving with a uniform velocity v1. It is given an impulse such that its velocity becomes v2. The impulse is equal to
NEET 1990
(a) m[|v2| − |v1|]
(b) 1/2 m (v2 ^2 - v1^2)
(c) m[v1 + v2]
(d) m[v2 − v1]
A block of mass m is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally so that the block does not slip on the wedge.The force exerted by the wedge on the block ( g is acceleration due to gravity) will be [2004]
NEET 2004
(a) mg/ cos θ
(b) mg cos θ
(c) mg sin θ
(d) mg
In carbon monoxide molecule, the carbon and the oxygen atoms are separated by a distance 1.12 × 10−10 m. The distance of the centre of mass, from the carbon atom is
(a) $0.64 × 10^{−10} m$
(b) $0.56 × 10^{−10} m$
(c) $0.51 × 10^{−10} m$
(d) $0.48 × 10^{−10} m$
[NEET 1997]
\[M\; r_{cm}=m_1 \; r_1 + m_2 \; r_2\]
\[\left (12u+16u \right) \; x = 12u \; (0) + 16u \left (1.12\times 10^{-10}\right)\]
\[x=0.64 \times 10^{-10}m\]