Showing posts with label Electric Field; Electric Field Lines and
Dipole. Show all posts
Showing posts with label Electric Field; Electric Field Lines and
Dipole. Show all posts
An electron falls from rest through a vertical distance h in a uniform and vertically upward directed electric field E. The direction of electric field is now reversed, keeping its magnitude the same. A proton is allowed to fall from rest in it through the same vertical distance h. The time of fall of the electron, in comparison to the time of fall of the proton is ?
A toy car with charge q moves on a frictionless horizontal plane surface under the influence of a uniform electric field E. Due to the force qE , its velocity increases from 0 to 6 m/s in one second duration. At that instant the direction of the field is reversed. The car continues to move for two more seconds under the influence of this field. The average velocity and the average speed of the toy car between 0 to 3 seconds are respectively ?
An electric dipole of moment p ′ is placed in an electric field of intensity ’ E ’. The dipole acquires a position such that the axis of the dipole makes an angle θ with the direction of the field. Assuming that the potential energy of the dipole to be zero when = 90◦ , the torque and the potential energy of the dipole will respectively be: ?
If a dipole of dipole moment p is placed in a uniform electric field E, then torque acting on it is given by ?
If a dipole of dipole moment \( \vec{p} \) is placed in a uniform electric field \( \vec{E} \), then the torque acting on it is given by ?
<p>(a) \( \vec{\tau} = \vec{p} \cdot \vec{E} \)</p>
<p>(b) \( \vec{\tau} = \vec{p} \times \vec{E} \)</p>
<p>(c) \( \vec{\tau} = \vec{p} + \vec{E} \)</p>
<p>(d) \( \vec{\tau} = \vec{p} - \vec{E} \)</p>
Answer : <p>(b) \(
\vec{\tau} = \vec{p} \times \vec{E} \)</p>
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