A parallel plate air capacitor has capacity ’ C ’ distance of separation between plates is ’ d ’ and potential difference ’ V ’ is applied between the plates. Force of attraction between the plates of the parallel plate air capacitor is ?
(a) \( \frac{C V^2}{2 d} \)
(b) \( \frac{C V^2}{d} \)
(c) \( \frac{C \cdot 2V^2}{2 d^2} \)
(d) \( \frac{C \cdot 2 V^2}{2 d^2} \)
Answer : (a) \( \frac{C V^2}{2 d} \)
\( \text{Energy} = \text{Work} \)
\( \frac{1}{2} C V^2 = F \cdot D \)
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