A series combination of n_1 capacitors, each of value C1, is charged by a source of potential difference 4 V. When another parallel combination of n2 capacitors, each of value C2. is charged by a source of potential difference V , it has the same (total) energy stored in it, as the first combination has. The value of C2, in terms of C1, is then ?
(a) \( \frac{2C_1 n_1}{n_2} \)
(b) \( \frac{16 n_2}{n_1} C_1 \)
(c) \( \frac{2 n_2}{n_1} C_1 \)
(d) \( \frac{16 C_1}{n_1 n_2} \)
Answer : (d) \( \frac{16 C_1}{n_1 n_2} \)
\( U_1 = U_2 \)
\( \frac{1}{2} \cdot \frac{c_1}{n_1} \cdot (4v)^2 = \frac{1}{2} \cdot n_2 c_2 v^2 \)
\( \frac{c_1 \cdot 16}{n_1 n_2} = c_2 \)
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