The electric intensity due to a dipole of length 10 cm and having a charge of 500μC, at a point on the axis at a distance 20 cm from one of the charges in air, is ?
(a) \( 6.25 \times 10^7 \ \text{N/C} \)
(b) \( 9.28 \times 10^7 \ \text{N/C} \)
(c) \( 13.1 \times 10^{11} \ \text{N/C} \)
(d) \( 20.5 \times 10^7 \ \text{N/C} \)
Answer : (a) \( 6.25 \times 10^7 \ \text{N/C} \)
\( l \ll r \)
\( E_{\text{axial}} = k \cdot \frac{2pr}{(r^2 - l^2)^2} \)
\( \underline{9 \times 10^9 \times 2 \cdot \left( 500 \times 10^{-6} \times \frac{10}{100} \right) \cdot \frac{25}{100}} \)
\( \left[ \left( \frac{25}{100} \right)^2 - \left( \frac{5}{100} \right)^2 \right]^2 \)
\( = 6.25 \times 10^7 \ \text{N/C} \)
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