Two point charges A and B, having charges +Q and −Q respectively, are placed at certain distance apart and force acting between them is F. If 25% charge of A is transferred to B, then force between the charges becomes: ?
(a) \( F \)
(b) \( \frac{9}{16} F \)
(c) \( \frac{16}{9} F \)
(d) \( \frac{4}{3} F \)
Answer : (b) \( \frac{9}{16} F \)
\( F = \frac{K \cdot Q \cdot (-Q)}{d^2} \)
\( F_2 = \frac{K \cdot \left( \frac{3}{4} Q \right) \cdot \left( -\frac{3}{4} Q \right)}{d^2} = \frac{9F}{16} \)
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