43. A converging beam of rays is incident on a diverging lens. Having passed through the lens the rays intersect at a point 15 cm from the lens on the opposite side. If the lens is removed the point where the rays meet will move 5 cm closer to the lens. The focal length of the lens is ?
(a) −10 cm
(b) 20 cm
(c) −30 cm
(d) 5 cm
Answer : (c) −30 cm
\( f = ? \quad (\text{negative concave}) \)
\( \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \)
\( = \frac{1}{15} - \frac{1}{10} \)
\( = -\frac{1}{30} \)
\( f = -30 \ \text{cm} \)
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