12. In Young’s double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduced to half. As a result the fringe width :
(a) is doubled
(b) is halved
(c) becomes four times
(d) remains unchanged
Answer : (c) becomes four times
\( \beta = \frac{\lambda D}{d} \)
\( \beta_2 = \frac{\lambda \, 2D}{d/2} \)
\( = 4 \frac{\lambda D}{d} \)
\( = 4\beta \)
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