Class 11 & 12 CBSE Physics Handbook

Class 11 & 12 CBSE Physics Handbook
CBSE NEET JEE

12. In Young’s double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduced to half. As a result the fringe width :

12. In Young’s double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduced to half. As a result the  fringe width :


(a) is doubled

(b) is halved

(c) becomes four times

(d) remains unchanged


Answer :  (c) becomes four times





\( \beta = \frac{\lambda D}{d} \)


\( \beta_2 = \frac{\lambda \, 2D}{d/2} \)


\( = 4 \frac{\lambda D}{d} \)


\( = 4\beta \)






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