Class 11 & 12 CBSE Physics Handbook

Class 11 & 12 CBSE Physics Handbook
CBSE NEET JEE

9. In Young’s experiment, two coherent sources are placed 0.90 mm apart and fringe are observed one metre away. If it produces second dark fringe at a distance of 1 mm from central fringe, the wavelength of monochromatic light used would be ?

9. In Young’s experiment, two coherent sources are placed 0.90 mm apart and fringe are observed one metre away. If it produces second dark fringe at a distance of 1 mm from central fringe, the wavelength of monochromatic light used would be ?


\( \text{(a) } 60 \times 10^{-4}\ \text{cm} \)

\( \text{(b) } 10 \times 10^{-4}\ \text{cm} \)

\( \text{(c) } 10 \times 10^{-5}\ \text{cm} \)

\( \text{(d) } 6 \times 10^{-5}\ \text{cm} \)


Answer :  \( \text{(d) } 6 \times 10^{-5}\ \text{cm} \)








\(\text{Maxima: } x_n = n \frac{\lambda D}{d}\)  

\(\text{Minima: } x_n = (2n-1)\frac{\lambda}{2}\frac{D}{d}\)  

\(= \frac{3}{2}\lambda \frac{D}{d}\)  

\(1 \times 10^{-3} = \frac{3}{2}\lambda \frac{1}{0.9 \times 10^{-3}}\)  

\(\lambda = \frac{2}{3} \times 0.9 \times 10^{-6}\)  

\(= 0.6 \times 10^{-6}\)  

\(= 6 \times 10^{-7}\)  

\(6 \times 10^{-7}\ \text{m}\)  

\(6 \times 10^{-7} \times 100\ \text{cm}\)  

\(= 6 \times 10^{-5}\ \text{cm}\)






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