2. A car moves a distance of 200 m. It covers the first half of the distance at speed 40 km/h and the second half of distance at speed v. The average speed is 48 km/h. Find the value of v.
(a) 56 km/h
(b) 60 km/h
(c) 50 km/h
(d) 48 km/h
Answer : (b) 60 km/h
\( \text{Speed}_{avg} = \frac{\text{Total distance}}{\text{Total time}} \)
\( 48 = \frac{200}{\frac{100}{40} + \frac{100}{v}} \)
\( 48 = \frac{2}{\frac{1}{40} + \frac{1}{v}} \)
\( \frac{1}{40} + \frac{1}{v} = \frac{2}{48} \)
\( \frac{1}{40} + \frac{1}{v} = \frac{1}{24} \)
\( \frac{1}{v} = \frac{1}{24} - \frac{1}{40} \)
\( \frac{1}{v} = \frac{40 - 24}{24 \times 40} \)
\( \frac{1}{v} = \frac{16}{24 \times 40} \)
\( \frac{1}{v} = \frac{1}{60} \)
\( v = 60 \text{ km/h} \)
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