4. If a car at rest accelerates uniformly to a speed of 144 km/h in 20 s, it covers a distance of ?
(a) 2880 m
(b) 1440 m
(c) 400 m
(d) 20 m
Answer : (c) 400 m
\(144\times\frac{1000\,\text{m}}{3600\,\text{s}} = 40\,\text{m/s}\)
\(144\,\text{km/h} = 40\,\text{m/s}\)
\(a=\frac{v_1-v_2}{t_1-t_2}\)
\(= \frac{40-0}{20-0}\)
\(= 2\,\text{m/s}^2\)
\(s=ut+\frac{1}{2}at^2\)
\(= 0+\frac{1}{2}\times 2 \times (20)^2\)
\(= 400\,\text{m}\)
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