15. The displacement of a particle varies with time (t) as: \( s = at^2 − bt^3 \) . The acceleration of the particle will be zero at time t equal to
(a) \( \frac{a}{b} \)
(b) \( \frac{a}{3b} \)
(c) \( \frac{3b}{a} \)
(d) \( \frac{2a}{3b} \)
Answer : (b) \( \frac{a}{3b} \)
\( \large s = A t^{\Large 2} - B t^{\Large 3} \)
\( \large v = \frac{\Large dS}{\Large dt} = 2A t - 3B t^{\Large 2} \)
\( \large a = \frac{\Large dV}{\Large dt} = 2A - 6B t = 0 \)
\( \large t = \frac{A}{3B} \)
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