A 4μF conductor is charged to 400 volts and then its plates are joined through a resistance of 1kΩ. The heat produced in the resistance is ?
(a) 0.16 J
(b) 1.28 J
(c) 0.64 J
(d) 0.32 J
Answer : (d) 0.32 J
\( H = i^2 R t \)
\( \quad = \frac{V^2}{R} \cdot t \)
This cannot be used because as \( q \) reduces, \( V \downarrow \ i \downarrow \). So it is not constant.
Energy stored in a capacitor is converted as heat energy.
Energy stored \( = \frac{1}{2} C V^2 \)
\( = \frac{1}{2} (4 \mu) \cdot 400^2 \)
\( = \frac{1}{2} \cdot 4 \times 10^{-6} \cdot 4^2 \times 10^4 \)
\( = 0.32\, \text{J} \)
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