The four capacitors, each of 25μF are connected as shown in fig. The dc voltmeter reads 200 V. The charge on each plate of capacitor is ?
\( \text{(a)} \ \pm 2 \times 10^{-3} \, \text{C} \)
\( \text{(b)} \ \pm 5 \times 10^{-3} \, \text{C} \)
\( \text{(c)} \ \pm 2 \times 10^{-2} \, \text{C} \)
\( \text{(d)} \ \pm 5 \times 10^{-2} \, \text{C} \)
Answer : \( \text{(b)} \ \pm 5 \times 10^{-3} \, \text{C} \)
\( Q = CV \)
\( = 25 \times 10^{-6} \times 200 \)
\( = 50 \times 10^{-6} \times 100 \)
\( = 5 \times 10^{-3} \)
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